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Wewaii [24]
3 years ago
12

The sum of three numbers is 123. The third number is 4 times the first. The second number is 9 more than the first. What are the

numbers?

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

1st = 19

2nd = 76

3rd = 28

Step-by-step explanation:

n + 4n + n + 9 = 123

6n + 9 = 123

6n = 114

n = 19

4(19) = 76

(19) + 9 = 28

Hope this helps :)

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A system of equations has infinitely many solutions. If 2y - 4x = 6 is one of the equations, which could be the other
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Answer:

-y = -2x - 3

Option 3

Step-by-step explanation:

When equations are equivalent, they will have infinitely many solutions.

If you want to find an equivalent equation, you can <u>multiply/divide every</u> term in the equation by the same number. You can also <u>rearrange</u> the equation.

Since the options mostly have "y" by itself, start by <u>rearranging</u> to isolate "y" in the given equation.

Move all the other numbers to the right of the equal sign except for "y". To move a number, apply its reverse operation to the entire equation.

Do reverse operations in reverse BEDMAS order.

2y - 4x = 6                Move "-4x" first. It's reverse is +4x.

2y - 4x + 4x = 6 + 4x

2y = 6 + 4x                Move the "2" in 2y. Divide the whole equation by 2.

2y/2 = 6/2 + 4x/2

y = 3 + 2x                  Rearrange to look like the answer choices.

y = 2x + 3

This equation looks like option 3 except every term has a different negative/positive.

y = 2x + 3         -y = -2x - 3

We can <u>multiply every term</u> by -1.

y = 2x + 3

y*-1 = 2x*-1 + 3*-1

-y = -2x + (-3)                Negative and positive make a negative

-y = -2x - 3                     Same as option 3

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