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4 years ago

Find the range of possible values of X when A < B

Mathematics

1 answer:

larisa [96]4 years ago

6 0

90 degrees, 80 degrees 110 and maybe not mayne 78 degress

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Guys can you please help me with this??<br> Thanks to whoever helps me

loris [4]

Answer:

188.5 $cm^2$

Step-by-step explanation:

The surface area of a cylinder can be found using the equation: $A=2\pi rh+2\pi r2$ .

When we plug in to this equation we get $2\pi (3)(7) + 2\pi(3^2)$ which equals 188.4955 which can be rounded up to 188.5 $cm^2$

8 0

3 years ago

The owner writes a line of best fit equation, shown below, to model the relationship between profit earned and month. y = 2,500x

Natali5045456 [20]

What is your question?

8 0

3 years ago

Find the two square roots of 0.25 write as a fraction first

s2008m [1.1K]

The fraction is 1/4 and the two square roots of 0.25 is 1/2 or 0.5. I hope this helped

4 0

4 years ago

What is perimeter and area of this object?

Artist 52 [7]

Answer:

Step-by-step explanation:

You have a circle with radius r = 3 ft and a 3-by-12 rectangle.

Area of circle = πr² = 9π ft²

Area of rectangle = 3 × 12 = 36 ft²

Total area = 36 + 9π ≈ 64.3 ft²

Perimeter of circle = 2πr = 6π ft

Perimeter of rectangular projections = 18 ft

Total perimeter = 6π +18 ≈ 36.8 ft

8 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago