Answer:
Addition of Polynomials
1Add: 3x3 – 5x2 + 8x + 10, 15x3 – 6x – 23, 9x2 – 4x + 15 and -8x3 + 2x2 – 7x.
2Add: 7a + 5b, 6a – 6b + 3c and -5a + 7b + 4c. ...
3Add: 3a2 + ab – b2, -a2 + 2ab + 3b2 and 3a2 – 10ab + 4b2 ...
4Add: 5x + 3y, 4x – 4y + z and -3x + 5y + 2z. First we need to write in the addition form. ...
Step-by-step explanation:
Hope it helps ya ItzAlex
Answer:
I'd think the first one would be correct. To determine whether or not athletes have an increase in vertical leap when wearing the shoes.
I'm not totally sure but this answer just seems the most correct. It would prove if the manufacturers clam is valid. You would have to other brand and models of shoes. You would also have to test the same kind of shoes ie, gym shoe vrs gym shoe instead of gym shoe vrs flip flop.
You would also have to use the different shoe on the same test group of users/athletes to keep a constant.
Hope I help.
Answer: The expressions for the length and width of the new patio are

And the area of the new patio is 384 sq. feet.
Step-by-step explanation: Given that Stephen has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.
The length of one side of the square patio is represented by x.
We are to write the expressions for the length and width of the new patio and then to find the area of the new patio if the original patio measures 20 feet by 20 feet.
Since Stephen wants to reduce width of the patio by 4 feet, so the width of the new patio will be

The length of the patio is increased by 4 feet, so the length of the new patio will be

Now, if the original patio measures 20 feet by 20 feet, then we must have

and

Therefore, the area of the new patio is given by

Thus, the expressions for the length and width of the new patio are

And the area of the new patio is 384 sq. feet.
If we had the info on with this "data" is, we then can solve it.
Answer:
SA = 680 units^2
V =1200 unit^3
Step-by-step explanation:
If the radius is 5 then the diameter is 2r = 2*5 = 10
The height would remain the same
Surface area of a prism is given by
SA = 2 (lw+lh+hw)
l =d = 10 w = d = 10 h = 12
SA = 2 ( 10*10 + 10 * 12+ 12* 10)
SA = 2( 100+120+120)
SA = 2(340)
SA = 680 units^2
V = l*w*h = 10*10*12 =1200 unit^3