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alisha [4.7K]
2 years ago
9

In "Happiness is...", which context clues can help you figure out the meaning of malcontent in the first sentence of paragraph 3

?
!! HELP PLEASE !!

- I'll give brainly to whoever is correct

Mathematics
2 answers:
andreev551 [17]2 years ago
4 0
The second one bc if you think about it
Andrej [43]2 years ago
4 0
The second one is correct
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Jacob wrote the expression shown. 10 + 5 + 4(72-6) What do these parentheses indicate in the expression? F Divide 10 by 5 before
icang [17]
You would multiply 4 by 72 then u multiply 4 * -6 then after that you would add 15
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Helppppppp Fassstttt
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The answers are:

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3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
4: Please help. What is the equation for ⨀C?
TEA [102]
It’s the second option
7 0
3 years ago
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Find x <br> –3(x – 4) + x = 2x – 12
raketka [301]

Answer:

x=6

Step-by-step explanation:

3 0
2 years ago
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