First, you need to rewrite the expression into binomial form, so you are working with two terms (as you world with a quadratic):
(x²)²-3(x²)-4=0
Now, you can place the x²s into brackets as the coefficient is now 1:
(x² )(x² )
Next, find out two numbers that add together to give you -3 and multiply to give -4 (these are the leftover integers after removing the x²s). These two numbers are -4 and 1.
Place the -4 and 1 into the brackets:
(x²-4)(x²+1)=0
Notice that the x²-4 is a difference of two squares, so can be further factorised into (x+2)(x-2)
This leaves you with a final factorisation of:
(x+2)(x-2)(x²+1)=0
Now we handle each bracket individually to obtain our four solutions for x:
x+2=0
x=-2
x-2=0
x=2
x²+1=0
x²=1
x=<span>±1</span>
The area of the figure is 19.
Answer:
Step-by-step explanation:
and 
and we are told that C is 6cm longer than A. That means that C = A + 6.
We are going to cross multiply each one of those ratios. The first one gives us
4A = 3B and the second one gives us
9B = 8C. But since C = A + 6, then
9B = 8(A + 6) and
9B = 8A + 48 and
Now we will solve the first equation above for A:
If 4A = 3B, then
and will use that as a sub for A in the second equation:
and
9B = 6B + 48 and
3B = 48 so
B = 16.
Now that we know B, we can use it to solve for A:
4A = 3(16) and
4A = 48 so
A = 12.
Then we can use that all the way back in the expression we set up for C:
C = A + 6 so
C = 12 + 6 so
C = 18
12 + 16 + 18 is the length of the string: 46cm
Answer:
x=3
Step-by-step explanation:
