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icang [17]
3 years ago
5

Which data set is the most spread from its mean?

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

the answer is B

Step-by-step explanation: each number on a c and d is 7-5 away from 23 but b has 36 which is 13 away from 23 and in all is the farthest plz mark brainlest

Digiron [165]3 years ago
6 0

Answer:

Tha mean is 23 which means there is no answer:)

<u>14, 26, 24, 28:</u> still 23

<u>22, 16, 18, 36:</u>STILL 23

<u>22, 28, 20, 22: </u><u>23</u>

<u>21, 19, 27, 25:</u> STILL 23

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5(x+3)=2x+3 what is x?
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2 years ago
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Algebra 1 question : Solve for x : 3 - 5x + 6 = 14x - 32 + 10(2-x)
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Hi there!

3 - 5x + 6 = 14x - 32 + 10(2 - x)
Work out the parenthesis.

3 - 5x + 6 = 14x - 32 + 20 - 10x
Combine like terms.

9 - 5x = 4x - 12
Subtract 9 from both sides.

- 5x = 4x - 21
Subtract 4x from both sides

- 9x =  - 21
Divide both sides by -9

x =  \frac{ - 21}{ - 9}  =  \frac{21}{9}  = 2 \frac{3}{9}  = 2 \frac{1}{3}



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Hallar el valor de x en 3(x-2)+4=x-5
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Step-by-step explanation:

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2 years ago
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If g(x)=1-3/4x find the values of g(0), and -5·g(4)-1
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Step-by-step explanation:

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3 years ago
A boy has 3 red , 2 yellow and 3 green marbles. In how many ways can the boy arrange the marbles in a line if: a) Marbles of the
Ilya [14]

Answer:

The total number of different arrangements is 560.

Step-by-step explanation:

A multiset is a collection of objects, just like a set, but can contain an object more than once.

The multiplicity of a particular type of object is the number of times objects of that type appear in a multiset.

Permutations of Multisets Theorem.

The number of ordered n-tuples (or permutations with repetition) on a collection or multiset of n objects, where there are k kinds of objects and object kind 1 occurs with multiplicity n_1, object kind 2 occurs with multiplicity n_2, ... , and object kind k occurs with multiplicity n_k is:

                                                 \begin{equation*}\frac{n!}{n_1!*n_2!*\dots * n_k!}\end{equation*}

We know that a boy has 3 red, 2 yellow and 3 green marbles. In this case we have n = 8.

If marbles of the same color are indistinguishable, then the total number of different arrangements is

{8 \choose 3, 2, 3}  = \frac{8 !}{3 ! 2 ! 3 !} = \frac{8\cdot \:7\cdot \:6\cdot \:5\cdot \:4}{2!\cdot \:3!}=\frac{6720}{2!\cdot \:3!}=\frac{6720}{12}=560

8 0
3 years ago
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