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Ann [662]
4 years ago
12

Hydrogen peroxide spontaneously decomposes to yeild water and oxygen. Balance this reaction.

Chemistry
2 answers:
gladu [14]4 years ago
5 0
C: 4 H on the left and right, 4 O on both sides making it balanced
solniwko [45]4 years ago
3 0

The answer here is C. 2,2,1 .

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How many liters of hydrogen gas are needed to react completely with 50.0 L of chlorine gas at STP ?
dolphi86 [110]

Answer:

50L of H2

Explanation:

First let us generate a balanced equation for the reaction

Cl2 + H2 —> 2HCl

From the equation above,

1L of Cl2 required 1L of H2 for complete reaction.

Therefore, 50L of Cl2 will also require 50L of H2 for complete reaction.

4 0
3 years ago
How many TOTAL ELECTRONS are in the compound CO2?
Liula [17]

Answer:

22 electrons are in the compound CO2. And the correct answer is Phosphorus tribromide.

Explanation:

7 0
3 years ago
What is the total number of atoms represented in the formula CuSO4*5H2O
Alenkinab [10]
There are 21 atoms represented in the formula :) hope this helped.
4 0
3 years ago
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
3 years ago
Consider the following reaction:
djverab [1.8K]
<span>Kc = [H2S]²*[O2]³ / [H2O]²*[SO2]²
Let x be the moles of H2S formed. Each mole of H2S takes one each mole of H2O and SO2 so after the reactions
[H2O] = 2.8 - x and [SO2] = 2.6 - x also for each mole of H2S, 1.5 moles of O2 are formed, so [O2] = 1.5*x
Kc = x²*(1.5*x)³ / (2.8 - x)²*(2.6 - x)²
Thus use 2.8 - x = 2.8 and 2.6 - x = 2.6 in the above equation for Kc:
Kc = x²*(1.5*x)³ / 2.8²*2.6² = 3.375x^5 / 2.8²*2.6² = 0.06368*x^5
x^5 = 1.3*10^-6 / 0.06368 = 2.0414*10^-5
x = 0.115M </span> hope it helps

4 0
3 years ago
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