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miv72 [106K]
3 years ago
9

How many moles are present in

Chemistry
1 answer:
olasank [31]3 years ago
4 0

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

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Answer:

                      Mass = 24.36 g of N₂

Explanation:

                   The balance chemical equation for the decomposition of NaNO₃ is as follow;

                                           2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

                 2 moles of NaNO₃ produces  =  3 moles of N₂

So,

              0.58 moles of NaNO₃ will produce  =  X moles of N₂

Solving for X,

                      X = 3 mol × 0.58 mol / 2 mol

                      X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂

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