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4 years ago

Round off 863 to one significant figure

1 answer:

6 0

Example: 863 is the number, when you pass more of 50 is for the other number and if you didn't pass the 50 is for 00.
ex. more than 851 is 900 and lees then 850 is 800
so the answer is 900

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???????????????????¿

Leni [432]

I'm just going to take a chance and say 1.A, and 2.D.

8 0

3 years ago

The ratio of the measures of the angles of a triangle is 6:2:7. Find the measure of the largest angle.

VLD [36.1K]

Answer:

Step-by-step explanation:

6x + 2x + 7x = 180 Every triangle has a measure of 180o

15x = 180 Divide by 15

x = 180/15

x = 12

The longest side will be 7x

7*12 = 84

3 0

3 years ago

NEED HELP ASAP!

Inga [223]

Answer:

The answer to your question is:

61.- 25

62.- 26

Step-by-step explanation:

61.-

2(5x + 5) + 2(2x) = 360

10x + 10 + 4x = 360

14x = 360 - 10

14x = 350

x = 350/14

x = 25

62.-

2(4x - 4) + 2(3x + 2) = 360

8x - 8 + 6x + 4 = 360

14x - 4 = 360

14x = 360 + 4

14x = 364

x = 364 / 14

x = 26

3 0

3 years ago

Consider the following population of N = 12 scores:

Goshia [24]

Answer:

Step-by-step explanation:

1. Find the minimun and maximun value of the data.

Minimun: 2

Maximun: 6

2. Calculate the range (R).

Range=

6 - 2=

3. Calculate the average.

Average= (Sum of all values) / N

Average= (2+3+3+3+4+4+4+4+5+5+5+6) / 12

Average= (48) / 12

Average= 4.

4. Calculate the M and round the value down.

$M=\sqrt{N} =\sqrt{12}=3.46$

$M= 3$

6. Calculate A.

$A=\frac{R}{M} =\frac{4}{3} =1.3333$

7. Craft your table.

(Check attatched image 1).

LL: Lower limit.

UL: Upper limit.

8. Calculate the limits and fill out the table.

LL / UL

2.00 2.00+A=3.33

3.33 3.3333 +A=4.66

4.66 5.99

5.99 7.32

7.32 8.65

Filled out table: check attatched image 2.

9. Check the data, count how many values fall into each interval and annotate on "frequency".

For example: There are 4 values between 2 and 3.33, these values are 2,3,3, and 3. Therefore, we write 4 on the frequency (absolute) cell for this row of the table. And we do the same for all the other classes.

Check attatched image 3.

10. Calculate the frequency (relative) for all classes.

For example: the first class (row 1 of the table) contains 4 values. Therefore, it's relative frequency would be:

$\frac{4}{N}=\frac{4}{12} =0.3333=$ 33.33%

Note: We divide by 12 because N=12.

Do the same for all the other rows and finish filling out the table.

Check attatched image 4.

-------------------------------------------------------------------------------------------------------

Extra. To make an histogram, take the interval and the absolute frequency and graph it in the fashion shown in attatched image 5.

7 0

2 years ago

The price of peaches at Al’s supermarket can be determined by the equation p=0.28n, where P is the price and n is the number of

Alina [70]

Answer:

k = 0.28

Step-by-step explanation:

The price of peaches at Al's supermarket can be determined by the equation P = 0.28n ........... (1)

where P is the price and n is the number of pounds of peaches.

Now, it is clear that the price of peaches is proportional to the number of pounds of peaches.

So, we can write,

P ∝ n

⇒ P = kn ............. (2) where k is the constant which we have to multiply to covert from proportionality to equation form.

Now, comparing equations (1) and (2) we get k = 0.28 which is the value of the constant of proportionality. (Answer)

8 0

3 years ago