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kicyunya [14]
3 years ago
10

Find the quotient of 3/4 and 5/6 in its simplest form​

Mathematics
1 answer:
Yuri [45]3 years ago
8 0

Answer:

= 1 R 2

= 1 2/3

Step-by-step explanation:

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WARRIOR [948]

Answer:

a

Step-by-step explanation:

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3 years ago
Which number can you add to get a sum of 0<br><br> A . -10<br> B. -5<br> C. 0<br> D. 5
Nikolay [14]
To figure this one out, my pre calculus teacher said to "plug and chug". Since you are adding each number to itself, A=-20, B=-10, C=0, and D=10. So your answer would be C.0
4 0
3 years ago
Erin bought a $205 smart phone, but her total was $217.30. What percent sales tax did she pay?
andrey2020 [161]

Answer:

6.00 %

Step-by-step explanation:

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6 0
2 years ago
Simplifly the expression 64^7/12
Evgesh-ka [11]

Answer:

8\sqrt{2}

Step-by-step explanation:

we have

64^{\frac{7}{12}}

we know that

64=2^{6}

substitute

64^{\frac{7}{12}}=(2^{6})^{\frac{7}{12}}\\ \\=(2)^{\frac{6*7}{12}} \\ \\=(2)^{\frac{7}{2}} \\ \\=\sqrt{2^{7}}\\ \\=2^{3}\sqrt{2} \\ \\=8\sqrt{2}

7 0
3 years ago
Prove that root 7 is irrational by the method of contradiction
Alchen [17]

Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

Therefore \sqrt7 is an irrational number.

8 0
3 years ago
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