If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.
d^2=x^2+x^2
d^2=2x^2
d=√(2x^2)
Since d=2r, r=d/2 so
r=(1/2)√(2x^2)
r=√((2x^2)/4)
r=√(x^2/2), since x=8
r=√(64/2)
r=√32
r=√(16*2)
r=4√2 in (exact)
r≈5.66 in (to nearest hundredth of an inch)
Divide 6 1/3 by 3/4
first, convert 6 1/3 to an improper fraction
6 1/3 --> 19/3
make the denominators match
19/3 --> 76/12
3/4 --> 9/12
then multiply 76/12 by the reciprocal of 9/12 (which is 12/9)
cross reduce, you get 76/9
convert back to a mixed number
76/9 --> 8 4/9
it would take 9 loads
It's three thousand and fifty
I’m not 100% but l’ll say go for D
Answer:
infinitely many solutions
Step-by-step explanation:
The two equations are the same line. When two lines are exactly the same, they have infinitely many solutions
