2 years ago

HELP ME PLEASE I'M BEING TIMED AND I DON'T WANT TO FAIL!!!! :(

1 answer:

klio [65]2 years ago

3 0

Answer is b, that’s the constant rate of increase

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victus00 [196]

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$\large\boxed{S.A.=4500\pi\ in^2\approx14130\ in^2}$

Step-by-step explanation:

The formula of a surface area of a ball (sphere):

$S.A.=\dfrac{4}{3}\pi R^3$

R - radius

We have R = 15in. Substitute:

$S.A.=\dfrac{4}{3}\pi(15^3)=\dfrac{4}{3}\pi(3375)=4500\pi\ in^2$

If you want to get an approximation, then:

$\pi\approx3.14\\\\S.A.\approx(4500)(3.14)=14130\ in^2$

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