E because 8*8=64 so 8/49*8/49 = 64/49
Answer:
Step-by-step explanation:
Givens
- The top soil weighs 40 pounds per bag.
- The mulch weighs 20 pounds per bag.
- The cart can only carry up to 480 pounds.
Notice that the restriction is a maximum of 480 pounds, that means the inequality must include the sign 
.
Now, let's call 
the top soil and 
the mulch, the inequality that represents this problem, would be
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
My boiii, tiger algebra helped me out a little on this one, I got 7c * sqrt(5)
Answer:
Answer is D on edge
Step-by-step explanation:
