Haha, this is more a problem of reading the question right :)
(x^2-4x+4)/(x^2+10x+25) * (x+5)/(x^2+3x-10)
Upon factoring the numerator and denominators...
[(x-2)^2/(x+5)^2]*(x+5)/((x+5)(x-2)) so on the right side the (x+5)s cancel
((x-2)^2/(x+5)^2)*1/(x-2) which is:
[(x-2)^2]/[(x+5)^2*(x-2)] now you can see that (x-2)^1 cancels
(x-2)/(x+5)^2 or if you prefer it expanded...
(x-2)/(x^2+10x+25)
Answer:
c
Step-by-step explanation:
vshsbjzjskkzizjz shjskzoa
Answer:
Step-by-step explanation:
5x^2+10x^1−6x^2x+3
=5x^2+10x+−6x^3+3
Answer:
=−6x^3+5x^2+10x+3
Answer:
For each choice of the first two digits you have 10 choices for the third digit. Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
I hope that helps! :)
First one is 97
2nd one is 8000
