Answer:
73
Step-by-step explanation:
Givens
d = 3
Equation 7d^2 + 10 = ?
Solution
7*3*3 + 10
7*9 + 10
63 + 10 = 73
That would be the term 11c2 because like 14c2, 11c2 has a constant, a variable and raised to the power of 2.
Step-by-step explanation:
Let
where



so that

Recall that the derivative of the product of functions is

so taking the derivatives of the individual functions, we get



So the derivative of y(x) is given by

or



Answer:
(a) f'(1)=-4
(b) y+4x-4=0
Step-by-step explanation:
<u>Tangent Line of a Function</u>
Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.
We are given

The derivative is

(a) The slope of the tangent line at (1,0) is


(b) The equation of the tangent line can be found with the general formula of the line:

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

Or, equivalently

Answer:
60x + 25 + 60y
Step-by-step explanation:
60 times x plus 60 times y plus 25