Answer: 5.14 cu in
Step-by-step explanation:
1/2 (π × d) + d, where d is the diameter of the semi
Perimeter = 1/2 (3.14 x 2) + 2
= 1/2 * 6.28 + 2
= 3.14 + 2
This problem can be solved by the chicken rabbits method or you can just do simple algebra.
I.) Chicken and rabbits method
First assume all 110 coins are dimes and none are quarters.
We will have a total value of 11 dollars
Now for each dime we switch out for a quarter, we adds 15 cents to the total value.
18.50-11=7.50 dollars
There are 750/15=50 group of 15 cents in the 7 dollars and 50 cents.
This also meant that we need to switch out 50 dimes for 50 quarters.
So we have 50 quarters.
That first method is very good and very quick once you get the hang of it, now I'm going to show you the algebraic way to solve this.
Let's say there are x dimes and y quarters.
Set up equation
x+y=110
10x+25y=1850
Now solve multiply first equation by 10
10x+10y=1100
subtract
15y=750
y=50
Now we set the numbers of quarters to y so the answer is 50 quarters.
I personally recommend using algebra whenever you can because the practice is very important and you will eventually get really fast at setting up and solving equations. The first method is faster in this case but the second is more generalize, hope it helps.
Answer:
Step-by-step explanation:
y=100+8x
Answer:
0.0085× 100= 0.85℅
Step-by-step explanation:
okay so you want 3/8 from 44 as percentage but how can you put the 3/8 on top of the 44 to multilply it by 100 to get the percentage, ofcourse we will have to change the 3/8 into a whole number. To do that we are going to do the following.
= 3 ÷ 8 = 0.375, so here you got a number that you can put on the 44.
Now to get the percentage we are going to do this:
0.375/44 × 100
= 0.0085 × 100 ( I solved the 0.375/44 as you know that division always comes first in maths)
= 0.85℅ ( I solved the 0.0085 × 100)
°•°•° I hope this helped sorry for taking long °•°•° May I get brainliest if you liked my ans im trying to lvl up ty and its okay if you don't want to
we will proceed to verify each case to determine the solution of the problem
we know that
If the ordered pair is a solution of the inequality , then the ordered pair must be satisfied the inequality
we have
<u>case A</u> point 
Substitute the values of x and y in the inequality
-------> is true
therefore
the pair ordered is a solution of the inequality
<u>case B</u> point 
Substitute the values of x and y in the inequality
-------> is false
therefore
the pair ordered is not a solution of the inequality
<u>case C</u> point 
Substitute the values of x and y in the inequality
-------> is true
therefore
the pair ordered is a solution of the inequality
<u>case D</u> point 
Substitute the values of x and y in the inequality
-------> is false
therefore
the pair ordered is not a solution of the inequality
<u>case E</u> point 
Substitute the values of x and y in the inequality
-------> is false
therefore
the pair ordered is not a solution of the inequality
therefore
<u>the answer is</u>
