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Grace [21]
3 years ago
15

Find the limit. (let g and h represent arbitrary real numbers. if an answer does not exist, enter dne.) lim x→∞ x2 + gx − x2 + h

x
Mathematics
1 answer:
seraphim [82]3 years ago
8 0
Wages wages wages wages wages wages wages wages wages wages wages wages wages wages wages wages wages 
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Hadley’s softball team has a phone tree in case a game is canceled. The coach calls 3 players. Then each of those players calls
Setler [38]
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5 0
3 years ago
According to the graph, what is the value of the constant in the equation below?
Virty [35]

According to the graph, the value of the constant in the equation below is 80 and is denoted as option D.

What is a Graph?

This is defined as a pictorial representation of data or variables in an organized manner.

From the equation:  Height = constant/width

We can pick any point(4,20) on the graph.

20 = c/ 4

c = 20 × 4 = 80

Read more about Graph here brainly.com/question/19040584

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6 0
2 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
3 years ago
Help me<br> On this pleaseee
Evgen [1.6K]
2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi

1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi

Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
Area Rectangle 2 = 280 mi * 170 mi = 47,600 mi²
Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²

Total Area = 6,400 mi² + 47,600 mi² + 9,800 mi² = <span>63,800 mi²</span>
4 0
3 years ago
The perimeter of the parallelogram is 62 cm.
Marina86 [1]
Flldkxlcclckk 929292 o
8 0
1 year ago
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