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Ivan
3 years ago
7

What is the answer to this? 2+8×(4+2)÷3−6

Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0
The answer would be 12.
Butoxors [25]3 years ago
4 0

Answer:

2+8×6÷3-6 = 2+48÷3-6 = 2+16-6 = 12

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If JM = 5x – 8 and LM = 2x - 6, which expression represents JL?
Anastasy [175]

Answer:

3x-2

Step-by-step explanation:

JK =JL+LM

5x-8=JL +(2x -6)

JL = 5x-8 -2x+6

JL = 3x-2

6 0
3 years ago
A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem
Ne4ueva [31]

Answer:

  • premium: 165 gallons
  • water: 120 gallons

Step-by-step explanation:

Let 'a' represent the amount of 95% antifreeze in the mix. Then the amount of water is (285 -a). The mix has this amount of antifreeze in it:

  0.95a +0(285 -a) = 0.55(285)

  a = 0.55/0.95(285) = 165 . . . gallons of 95%

  285 -a = 285 -165 = 120 . . . . gallons of water

There are 120 gallons of water and 165 gallons of premium antifreeze in the mixture.

6 0
2 years ago
What does 1/2 Equivalent to.
Natali5045456 [20]
As a decimal it is equivalent to 0.5
As a fraction it can be equivalent to 2/4, 3/6, 4/8, 5/10 and so on. Hope this helps :)
4 0
2 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
2 years ago
Write an equation of the line with a slope of -7 and y-intercept 1
AveGali [126]
Y=-7x+1

Hope this helps
3 0
3 years ago
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