Answer: First off thats not how you ask for help, by calling us "smart math people" that could offend someone...Second off the answer is 10 because
Step-by-step explanation:
A^2 + B^2 = C^2
6^2 + 8^2 = C^2
36 + 64 = 100 square root that = 10
Answer: 10
Answer:
I think answer is 87<180 or maybe 87<12*15
A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)
The amount of sample that will remain after 4000 years is; 4.8357 mg
The number of years that it will take for only 17 mg of the sample to remain is; 1076 years
<h3>How to solve exponential decay function?</h3>
A) Using the model for radioactive decay;
m(t)= m₀e^(-rt)
where;
m₀ is initial mass
r is rate of growth
t is time
Thus, we are given;
m₀ = 27 mg
r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043
and so we have;
m(t) = 27e^(-0.00043t)
c) The amount that will remain after 4000 years is;
m(4000) = 27e^(-0.00043 * 4000)
m(4000) = 27 * 0.1791
m(4000) = 4.8357 mg
d) For 17 mg to remain;
17 = 27e^(-0.00043 * t)
17/27 = e^(-0.00043 * t)
In(17/27) = -0.00043 * t
-0.4626/-0.00043 = t
t = 1076 years
Read more about Exponential decay function at; brainly.com/question/27822382
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Answer:
4times tall
Step-by-step explanation:
Volume of the boxes = Base area × height
Volume of the first box V1 = A1h1
Given the base of the first box to be 5cm, the base area:
A1 = 5cm×5cm = 25cm²
Volume of the first box V1 = 25h1... 1
Similarly, volume of the second box
V2 = A2h2
Given the base of the second box to be 10cm, the base area:
A2= 10cm×10cm = 100cm²
Volume of the second box
V2 = 100h2... 2
If the two boxes have the same volume, then V1 = V2
25h1 = 100h2
divide both sides by 25
25h1/25 = 100h2/25
h1 = 4h2
Since the height of the smaller box is represented as h1, then the height of the smaller base is 4 times tall.
Answer:
10) min = 5
max = 225
IRQ = 60
That's all I got
sorry
Step-by-step explanation:
