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seraphim [82]
3 years ago
6

Please help Iv'e been waiting all day!

Mathematics
1 answer:
vichka [17]3 years ago
5 0
The answer is C. 791.3 m3

The volume of the cylinder (V) is:
V = π · r² · h        (r - radius, h - height)

It is known:
π = 3.14
d = 12 m ⇒ r = d/2 = 12/2 = 6 m
h = 7m

Thus:
V = π · r² · h = 3.14 · 6² · 7 = 3.14 · 36 · 7 = 791.28 m³ ≈ 791.3 m³
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If the perimeter of the following triangle is 7x-2, what is the length of the unknown side?
Alinara [238K]

7x-2-(3x-9)-(x+7)

=7x-2-3x+9-x-7

=7x-3x-x-2+9-7

=3x

4 0
3 years ago
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Verizon [17]
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8 0
3 years ago
Complete the statements.
spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

3tan^2(x)-1 =0

Lets assume tan(x) = u

3u^2(x)-1 =0

Now we solve for 'u'

add 1 on both sides

3u^2(x) =1, divide both sides by 3

u^2 = \frac{1}{3}

Take square root on both sides

u = +-\frac{1}{\sqrt{3} }

We replace tan(x) for 'u'

tan(x) = +-\frac{1}{\sqrt{3} }  

x = 30 because tan(30) =+\frac{1}{\sqrt{3} }  in first quadrant

      x = 30      (tan is positive in first quadrant)

tan(x) =-\frac{1}{\sqrt{3} }                                                    

  x = 150 because tan(150) =-\frac{1}{\sqrt{3} }  in second quadrant

     tan is negative in second quadrant




4 0
3 years ago
PLZ HELP!!!!!....................
forsale [732]
It’s c. Where the two planes intersect
5 0
3 years ago
3. Janet is flying a kite on a string that is 75m long. The kite is 62m above the ground. Estimate the distance between Janet an
konstantin123 [22]
Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62. 
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.

To find the missing distance in the right triangle. You have to use the Pythagorean Theorem.  I set it up and solve it below.

a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
x = 42.2 (about)

3 0
3 years ago
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