Please help Iv'e been waiting all day!

1 answer:

5 0

The answer is C. 791.3 m3

The volume of the cylinder (V) is:
V = π · r² · h (r - radius, h - height)

It is known:
π = 3.14
d = 12 m ⇒ r = d/2 = 12/2 = 6 m
h = 7m

Thus:
V = π · r² · h = 3.14 · 6² · 7 = 3.14 · 36 · 7 = 791.28 m³ ≈ 791.3 m³

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Tema [17]

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8 0

3 years ago

Estimate the length of one side of a square floor, if the area is 320 square feet. Give the whole number that is closest to the

RSB [31]

Let us assume the length of a side of the square floor = x feet
Area of the square floor as given in the question = 320 square feet
Then
x^2 = 320
x^2 = (17.89)^2
Then
x = 17.89
= 18 feet approx

From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the second option or option "B".

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3 years ago

(12x + y + z = 26

mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

$\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}26\\17\\23\end{array}\right]$ .

Step 3:

The linear system B is represented as

$\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}23\\17\\26\end{array}\right]$ .

Step 4:

The linear system C is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}4\\11\\12\end{array}\right]$ .

Step 5:

The linear system D is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}12\\11\\4\end{array}\right]$ .