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Tpy6a [65]
4 years ago
12

Solve 3x2 = −12x − 15. x = −4 ± 2i x = −4 ± i x = −2 ± 2i x = −2 ± i

Mathematics
1 answer:
diamong [38]4 years ago
3 0
ANSWER

x = - 2 \pm i

EXPLANATION

We use the method of completing the squares.

The equation is
3 {x}^{2} = - 12x - 15

We rewrite the above equation to obtain;

3 {x}^{2} + 12x = - 15

We divide through by 3 to obtain;

{x}^{2} + 4x = - 5

We add half the coefficient of
x

to both sides of the equation to get,

{x}^{2} + 4x + {2}^{2} = - 5 + {2}^{2}

The right hand side is now a perfect square.

{(x + 2)}^{2} = - 1

We now take square root of both sides to get;

x + 2 = \pm \sqrt{ - 1}

We add -2 to both sides,

x = - 2 \pm \sqrt{ - 1}

We simplify to obtain,

x = - 2 \pm i
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\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
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\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
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with that template in mind, let's see.

to the left by 3 units, C = +3
up by 1  unit, D = 1

\bf g(x)=-x^2\\\\\\ g(x)=-1(1x+\stackrel{C}{0})^2+\stackrel{D}{0}\implies g(x)=-1(1x+3)^2+1
\\\\\\
g(x)=-(x+3)^2+1\impliedby f(x)\qquad \qquad f(-1.5)=-[(-1.5)+3]^2+1

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