What are the coordinates of point A′ if triangle ABC is rotated 90° to produce the image triangle A′B′C′?
1 answer:
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9514 1404 393
Answer:
55,637.8 square inches
Step-by-step explanation:
We can find side n using the Law of Sines:
n/sin(N) = p/sin(P)
n = p(sin(N)/sin(P)) = 600·sin(64°)/sin(96°)
n ≈ 542.246913 . . . . inches
The angle O is ...
O = 180° -N -P = 180° -64° -96° = 20°
Then the area is ...
A = 1/2·np·sin(O)
A = (1/2)(542.246913 in)(600 in)·sin(20°) ≈ 55,637.81008 in²
The area of ∆NOP is about 55,637.8 in².
