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Alex777 [14]
4 years ago
8

Write a word problem for the equation. 1/2 (x-4) = 1/3x + 2

Mathematics
1 answer:
Ganezh [65]4 years ago
3 0

Answer:

Half the age of Carlos four years ago is 2 years more than one-third his current age.

Step-by-step explanation:

We want to write a word problem for the equation.

\frac{1}{2} (x - 4) =  \frac{1}{3}x + 2

Let x represent the present age of Carlos.

Four years ago, Carlos was x-4 years.

Half his age four years ago is ½(x-4)

Two years more than one-third his current age is ⅓x+2

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Simplify this expression<br> 45p - 9p + 8
beks73 [17]

Answer:

45p-9p+8 simplified is 36p+8

3 0
3 years ago
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A postage stamp is shaped like a rectangle with a perimeter of 88 millimeters. The length (x) is 10 millimeters less than twice
Oxana [17]
The answer would be D. It says the length is 10 millimeters less than TWICE the width, so it would be 10 millimeters greater than the original width.
5 0
3 years ago
Find the volume of the solid that lies inside both the cylinder x 2 y 2 = 1 and the sphere x 2 y 2 z 2 = 16
IrinaVladis [17]

The volume of the solid that lies inside both the cylinder x² + y² = 1 and the sphere x² + y² + z² = 16 is 24.74 cubic units.

<h3>What is the volume of the solid?</h3>

Find the volume of the solid that lies inside both the cylinder x² + y² = 1 and the sphere x² + y² + z² = 16

From the sphere and cylinder, the cylindrical coordinate will be

z = \pm \sqrt{16 - r^2}

And the radius of the cylinder is |r| < 1 and the 0 ≤ θ ≤ 2π.

Then the volume will be given as

\rm V = \int _0^{2\pi} \int _0^1 \int _{- \sqrt{16 - r^2}}^{\sqrt{16-r^2}} \left ( r \ dz \ dr \ d\theta  \right ) \\\\\\V = 2\pi \int_0^1 \left ( 2r\sqrt{16-r^2} \right ) \ dr\\\\\\V = 4\pi \left [ -\dfrac{1}{3} (16 - r^2)^{3/2} \right ]\\\\\\V = \dfrac{4\pi}{3} \left ( 16^{3/2} - 15^{3/2} \right )\\\\\\V = 24.74

More about the volume of the solid link is given below.

brainly.com/question/23705404

#SPJ4

7 0
2 years ago
Here's the question ​
zheka24 [161]

Answer:

60

Step-by-step explanation:

perimeter (p) = 8 + 17 + 15 = 40

semi-perimeter (s) = p/2 = 20

Area = square root of s(s-a)(s-b)(s-c) where a,b,c are the sides of the triange by Herons formula.

Therefore, area = 20(20-8)(20-15)(20-17) = square root of 3600 = 60

4 0
3 years ago
Are these answers correct
Reika [66]

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
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