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Alex777 [14]
4 years ago
8

Write a word problem for the equation. 1/2 (x-4) = 1/3x + 2

Mathematics
1 answer:
Ganezh [65]4 years ago
3 0

Answer:

Half the age of Carlos four years ago is 2 years more than one-third his current age.

Step-by-step explanation:

We want to write a word problem for the equation.

\frac{1}{2} (x - 4) =  \frac{1}{3}x + 2

Let x represent the present age of Carlos.

Four years ago, Carlos was x-4 years.

Half his age four years ago is ½(x-4)

Two years more than one-third his current age is ⅓x+2

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Gummy bears: red or yellow? Chance (Winter 2010) presented a lesson in hypothesis testing carried out by medical students in a b
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Answer:

z=\frac{0.802 -0.5}{\sqrt{\frac{0.5(1-0.5)}{121}}}=6.64  

p_v =2*P(z>6.64)=3.14x10^{-11}  

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Step-by-step explanation:

Data given and notation

n=121 represent the random sample taken

X=97 represent the people who identify the color of the gummy bear

\hat p=\frac{97}{121}=0.802 estimated proportion of people who identify the color of the gummy bear

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Part a

For this case the parameter that we want to test is 0.5 for the proportion of the population of students will correctly identify the color

Part b: Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that there is no relationship between color and gummy bear flavor (population proportion different from 0.5).:  

Null hypothesis:p=0.5  

Alternative hypothesis:p \neq 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Part c: Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.802 -0.5}{\sqrt{\frac{0.5(1-0.5)}{121}}}=6.64  

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It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

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