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kipiarov [429]
3 years ago
7

Suppose that the population of deer in a state is 19,900 and is growing 3% each year. Predict he population after 10 years.

Mathematics
1 answer:
mezya [45]3 years ago
5 0
P=19,900×(1+0.03)^(10)
P=26,743.94
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Between which two ordered pairs does the graph of f(x) = one-halfx2 + x – 9 cross the negative x-axis?
Anit [1.1K]

Answer:

Step-by-step explanation:

we have that

f(x) = x^2 + x - 9

Using a graph tool

see the attached figure

The function represent a vertical parabola that open up

the vertex is a minimum-------> is the point (-0.5, -9.3)

The x-intercepts are the points when the y coordinate is equal to zero

The x-intercepts are the points (-3.5, 0)  and (2.5, 0)

so

the function cross the negative x-axis at point

therefore, the answer is

(-4, 0) and (-3, 0)

6 0
3 years ago
Read 2 more answers
Write an equation for this relationship.
disa [49]

Answer:

y=18.5x

Step-by-step explanation:

74-55.5=18.50

92.50-74=18.50

111-92.5=18.50

(3,55.50)

y=18.5x +b

55.50=18.5(3)+b

55.50=55.50+b

b=0

8 0
3 years ago
when you divide a fraction less than 1 by a whole number greater than 1, is the quotient less than, greater than, or equal to th
ratelena [41]

Answer:

less than

Step-by-step explanation:

7 0
3 years ago
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Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number
sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

E(X)=\sum x\cdot P(X=x)

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner:   1           2           3          4           5              6

Amount earned (<em>X</em>):   $1        $4         $7        $10     -$8.75     -$8.75

Probability:                 1/6       1/6         1/6        1/6         1/6           1/6

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x\cdot P(X=x)

         =(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})

         =\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}

         =\frac{1+4+7+10-8.75-8.75}{6}

         =0.75

Thus, the expected value of playing the game is $0.75.

5 0
3 years ago
4 2/3 divided by 1/2 = what plsssss helppp
MAXImum [283]

Answer:

8.66

Step-by-step explanation:

6 0
3 years ago
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