Question

Find the value of x in the triangle shown below

Answer 1

Answer:

x = 12

Step-by-step explanation:

Using the Pythagorean theorem where c = 13, and b = 5, we get (a = x):

$a^2 + 5^2 = 13^2$

Solving for a:

$a^2 = 13^2-5^2$

$a =\sqrt{13^2-5^2} = \sqrt{144}=12$

Answer 2

Answer:

x=12

Step-by-step explanation:

The given triangle is a right angled triangle, where the base and the height are given.

The third side can be find by using the Pythagorean Theorem, i.e

$(Hypotenuse)^2=(Perpendicular)^2+(base)^2$

Hypotenuse= 13

Perpendicular= 5

Base= x

          $13^2=5^2+x^2$

          $169=25+x^2\\\\x^2=169-25\\\\x^2=144\\\\x=12$

The Value of 'x' is 12