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2 years ago

PLease help me i beg you i really need help

Mathematics

1 answer:

BigorU [14]2 years ago

7 0

1)
f(x)=tan 90º=indeterminated or ∞

Answer: y-value=indeterminated or ∞.

2)
Law of sines:
a/sin A=b/ sinB
In this case:
24 /sin 92º=7/sin Z
sin Z=(7*sin 92º)/24=0.29148...≈0.29

Z=arc sin (0.29)=16.95º

Answer: Z=16.95º.

3)
Law of cousines:
a²=b²+c²-2bc(cos A)
In this case:
12²=22²+19²-2(22)(19)cos T
144=484+361-836 cos T
-836 cos T=144-484-361
-836 cos T=-701
cos T=-701/-836
cos T=0.83851...≈0.84
T=arc cos (0.84)=33.02

Answer: T=33.02º

4)
The hypotenuse would be EF, because it is in front of the right angle.
The legs would be EG and FG

Answer: The legs would be EG and FG.

5)
cot Ф= adjacent /opposite=10/24=5/12

Answer: cot Ф=5/12

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The product of twice a number and four is the same as the difference of seven times the number and 5/3

gavmur [86]

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2N÷4=7N-5/3

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2 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

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6 months ago

A mechanic uses a mechanical lift to raise a car. The car weighs 10,200 N. The work required to do this was 22,440 J.

Neporo4naja [7]

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2 years ago

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2 years ago

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How do I factor 2x^2 + 11x +5

ASHA 777 [7]

(2x+1)(x+5) is the answer.

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