Instructions: Factor 715 as a product of primes.

Mathematics

1 answer:

Drupady [299]4 years ago

8 0

Answer:

{1, 5, 143}

Step-by-step explanation:

715 is evenly divisible by 5, so one factor of 715 is 5 and the next is 715/5, or 143. 143 is not factorable further. Thus, the factors of 715, in ascending order, are 1, 5 and 143.

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-------------------------------\\\\
\begin{array}{ccll}
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\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
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