I believe the slope of the line is 1/3
\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Answer:
I think its c?
Step-by-step explanation:
Im sorry if its wrong.
Answer:
$337.5
Step-by-step explanation:
He would get $337.5 because if he gets $11.25 every hour you just multiply $11.25 by 30 hours.
Answer:
Step-by-step explanation:
1) The z value was determined using a normal distribution table. From the normal distribution table, the corresponding z value for a 94% confidence interval is 1.88
The correct option is D
2) if 70% of all internet users experience e-mail fraud. It means that probability of success, p
p = 70/100 = 0.7
q = 1 - p = 1 - 0.7 = 0.3
n = number of selected users = 50
Mean, u = np = 50×0.7 = 35
Standard deviation, u = √npq = √50×0.7×0.3 = 3.24
x = number of internet users
The formula for normal distribution is expressed as
z = (x - u)/s
We want to determine the probability that no more than 25 were victims of e-mail fraud. It is expressed as
P(x lesser than or equal to 25)
The z value will be
z = (25- 35)/3.24 = - 10/3.24 = -3.09
Looking at the normal distribution table, the corresponding z score is 0.001
P(x lesser than or equal to 25) = 0.001
