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Rudiy27
3 years ago
12

The square root of -108

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0
Because the number you provided is negative, we won't get a real answer instead a complex answer.

Now simplify the square root.

To simplify a square root, find two factors where one of the factors is a perfect square.

\sqrt{-108} = \sqrt{(-3)(36)} = \sqrt{-3}\sqrt{36} = 6\sqrt{(-1)(3)} = 6\sqrt{(-1)}\sqrt{3} = 6i\sqrt{3}
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UkoKoshka [18]

The examples of geometric names include triangle, circle, square, rectangle, pentagon, etc.

<h3>What is a geometric name?</h3>

Your information is incomplete as the shapes aren't given. Therefore, an overview will be given.

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7 0
2 years ago
What is the equation of the line shown in this graph
prisoha [69]
Slope = (2+4)/(1-4) = 6/-3 = -2
passing thru (1.2)
y = mx + b
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equation
y = -2x + 4
7 0
2 years ago
F (x) = 3x^2+ 5 x -14
elena-14-01-66 [18.8K]

Here is the answer

6 0
2 years ago
I NEED HELP ASAP PLEASE! ​
Brilliant_brown [7]

Answer:

AB = 2

Step-by-step explanation:

Using the secant- secant theorem, that is

PA × PB = PD × PC , substitute values

10(10 + AB) = 8(8 + 7)

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8 0
2 years ago
Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0
3 years ago
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