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cestrela7 [59]
3 years ago
15

In a lake there are 53 blue tail fishes and 40 yellow tail fishes. we capture 12 fishes. what is the most probable number of blu

e tail fishes?
Mathematics
1 answer:
luda_lava [24]3 years ago
7 0
In general, the most probable distribution is in the ratio of the respective types, namely
Number of blue tails
=12*(53/(53+40))
=6.84
To check between 6 or 7, we use the hypergeometric distribution:

P(B=6)
=C(40,6)C(53,6)/(C(93,12)
=3838380*22957480/416579843773639
=0.211530
P(B=7)
=C(40,5)C(53,7)/(C(93,12)
=658008*154143080/416579843773639
=65563917120/269282381237
=0.243476

Hence the most probable number of blue tail fishes is 7


Note: it would be prudent to calculate P(B=8)=0.194443 to show that P(B=7) is indeed the highest value.
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Read 2 more answers
9(5x + 1) ÷ 3y
alexdok [17]

The expression obtained after solving the given expression is,\rm \frac{(15x+3)}{y}

<h3>What is a BODMAS rule?</h3>

For the Bracket, Order, Division, Multiplication, Addition, and Subtraction rules, BODMAS stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction.

Given expression ;

9(5x + 1) ÷ 3y

Follow the BODMAS rule;

Step 1; Divide

\rm \frac{9(5x+1)}{3y} \\\\ \frac{3(5x+1)}{y} \\\\

Step 2; Multiply

\rm \frac{9(5x+1)}{3y} \\\\ \frac{(15x+3)}{y} \\\\

Hence the expression obtained after solving the given expression is,\rm \frac{(15x+3)}{y}

To learn more about the BODMAS rule, refer to brainly.com/question/23827397.

#SPJ1

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