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cestrela7 [59]
3 years ago
15

In a lake there are 53 blue tail fishes and 40 yellow tail fishes. we capture 12 fishes. what is the most probable number of blu

e tail fishes?
Mathematics
1 answer:
luda_lava [24]3 years ago
7 0
In general, the most probable distribution is in the ratio of the respective types, namely
Number of blue tails
=12*(53/(53+40))
=6.84
To check between 6 or 7, we use the hypergeometric distribution:

P(B=6)
=C(40,6)C(53,6)/(C(93,12)
=3838380*22957480/416579843773639
=0.211530
P(B=7)
=C(40,5)C(53,7)/(C(93,12)
=658008*154143080/416579843773639
=65563917120/269282381237
=0.243476

Hence the most probable number of blue tail fishes is 7


Note: it would be prudent to calculate P(B=8)=0.194443 to show that P(B=7) is indeed the highest value.
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\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

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Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2-3-6\\

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<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2-2-6\\

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\rm\implies y = -1^2-1-6\\

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\rm\implies y = 1^2+1-6\\

\rm\implies y = 2 -6

\rm\implies y = -4

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\rm\implies y = 2^2+2-6\\

\rm\implies y = 4 +2-6\\

\rm\implies y = 2

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\rm\implies y = 3^2+3-6\\

\rm\implies y = 9 +3-6\\

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