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harina [27]
3 years ago
10

Sample size non-inferiority tests for two means using differences

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0
What's the question?
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Solve for x<br><br> - x + 2 = x - 5 - 3x
storchak [24]
The answer is x=-7 you just have to cancel the like factors out n you don’t have to divide nothing in this equation.
7 0
4 years ago
5×6 ÷ (9-4)= use PEMDAS FORGOT HOW TO DO THIS
Morgarella [4.7K]

PEMDAS = Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction

This is the order of how to solve the problems. For this problem, we can start with parentheses since it has that in this equation.

5 x 6 ÷ (5)

The next step is to do Multiplication.

30 ÷ 5

Finally Division.

6

This is your final answer.

Hope that helps!

5 0
3 years ago
Read 2 more answers
Question in pic. Plz open the pic for the question ..corect gets branliest
mel-nik [20]
<h2><u>Answer with explanation</u>:</h2>

Given: In Δ ABC and ΔAEC,

AB=BC and AD=CD

i) In ΔADB and CBD, we have

AD = DC        [given]

AB=BC           [given]

DB= DB           [given]

⇒ ΔADB ≅ΔCDB   [By SSS congruence rule]

⇒ ∠ADB ≅∠CDB       ...(i)           [Corresponding parts of congruent triangles are congruent]

Since AC is a straight line,

∠ADB+∠CDB = 180°   [Linear pair]

⇒∠ADB+∠ADB=180°   [from (i)]

⇒2 ∠ADB=180°  

⇒∠ADB=90°  =∠CDB

Also ∠ADB+∠ADE=180°   [Linear pair]

⇒∠ADE=180°-∠ADB  = 180°-90°

⇒∠ADE=90°, i.e. ∠ADE is a right triangle.

Similarly, ∠CDB+∠CDE=180°

⇒∠CDE=90°

ii) Now, in ΔADE and CDE

AD= CD   [given]

ED=ED   [Common]

∠ADE= ∠CDE = 90°

⇒ΔADE ≅ CDE   [By SAS congruence rule ]

⇒AE=EC   [Corresponding parts of congruent triangles are congruent]

Hence proved.

6 0
3 years ago
The area of a rectangular equals length times width.A single tennis court has an area of 2106 ft2 and a width of 27 ft.Find the
madam [21]
The answer is 78 because you divide 2106 and 27 to find the length
4 0
3 years ago
Harold earns $10.50 per hour working at a doctors office. On Monday he spent 1 5/12 hours filing paperwork, 1 3/4 sending e-mail
agasfer [191]
The answer is $73.50.
5 0
3 years ago
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