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guajiro [1.7K]
3 years ago
5

How can I solve this hard equation

Mathematics
2 answers:
Alex787 [66]3 years ago
4 0

for the first one you can use division.

The second one is subtract 39. 

Dominik [7]3 years ago
4 0
Division is the answer
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(7w+4h)+ 5(2w+3h)- 2(w+h)
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The sum of two confescutive integers is at least 46. What is the least possibly pair of integers?
dezoksy [38]
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.

1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46

So we have two possibilities: either #2 or #4. Find least possible pair of integers.

x= first integer
x+1= second integer

x + (x+1) >= 46
2x + 1 >=46
2x>=45
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Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.

Hope this helps! :)
3 0
3 years ago
Write a quadratic function f whose zeros are 3 and 12.<br> f(x) = ?
ololo11 [35]

Answer:

The above equation is a quadratic function whose zeroes are 3 and 12.

Step-by-step explanation:

The general quadratic equation is given by :

ax^2+bx+c=0

It is given that, the zeroes of a quadratic function are 3 and 12. It means they must be factors of it such that,

(x-3)=0\\\\(x-12)=0

So, we can write as :

(x-3)(x-12)=0

Multiplying both factors,

(x-3)(x-12)=0\\\\x^2-12x-3x+36=0\\\\x^2-15x+36=0

So, the above equation is a quadratic function whose zeroes are 3 and 12.

5 0
3 years ago
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Mademuasel [1]

Answer:

Step-by-step explanation:

∠5 + ∠4 = 180°

4x° + 2x° = 180°

6x° = 180°

x = 30

6 0
3 years ago
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