Answer:
<u>m<DXF=52°</u>
<u>m<DXF=52°m<DYG=</u><u>9</u><u>4</u><u>°</u>
<u>m<DXF=52°m<DYG=94m<DG=20</u><u>°</u>
Step-by-step explanation:
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Simplify the given expression. 2(4 - 2x + y) - 4(5 + x - y)
1 answer:
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Answer:
Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.
Step-by-step explanation:
We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each survey.
The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.
Let X = <u><em>numbers of seals observed</em></u>
The z score probability distribution for normal distribution is given by;
Z = ~ N(0,1)
where, = population mean numbers of seals = 73
= standard deviation = 14.1
Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X 50 seals)
P(X 50) = P(
) = P(Z
-1.63) = 1 - P(Z < 1.63)
= 1 - 0.94845 = <u>0.0516</u>
The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.
There's a right angle that they want you to make a rectangle out of. I'm ignoring that and using each of the five sides to make a triangle with the origin.
A. Five triangles, zero rectangles.
B.
AB=4, the difference of the x coordinates since the y coordinates are the same
AE = 5, the difference in the y coordinates since the x coordinates are the same
C. We'll use the Shoelace Formula, adding up all those triangles I made. A triangle with vertices (0,0), (a,b), (c,d) has signed area A = (1/2)(ad-bc). We go around counterclockwise so they all have positive areas, starting with AE, then ED, DC, CB, BA.
Area = (1/2) ( (-2)(-2) - 3(-2) + (-2)(-4) - (-2)(0) + 0(-2) - (-4)(5) + 5(3) - (-2)(2) + 2(3) - (3)(-2))
Area = 69/2
