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Answer with explanation</u>
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Given: A water bottle cost 4 dollars and a hat cost 6 dollars.
Let x = Number of water bottles
y = Number of hats
The club wants to raise $1200.
i.e. Required equation : 4x+6y=1200
At x=0,
![0+6y=1200\Rightarrow\ y=\dfrac{1200}{6}\Rightarrow\ y=200](https://tex.z-dn.net/?f=0%2B6y%3D1200%5CRightarrow%5C%20y%3D%5Cdfrac%7B1200%7D%7B6%7D%5CRightarrow%5C%20y%3D200)
At x= 300
![4(300)+6y=1200\\\Rightarrow\ 1200+6y=1200\Rightarrow\ 6y=0\Rightarrow y=0](https://tex.z-dn.net/?f=4%28300%29%2B6y%3D1200%5C%5C%5CRightarrow%5C%201200%2B6y%3D1200%5CRightarrow%5C%206y%3D0%5CRightarrow%20y%3D0)
At x= 240
![4(240)+6y=1200\\\Rightarrow\ 960+6y=1200\Rightarrow\ 6y=240\Rightarrow y=40](https://tex.z-dn.net/?f=4%28240%29%2B6y%3D1200%5C%5C%5CRightarrow%5C%20960%2B6y%3D1200%5CRightarrow%5C%206y%3D240%5CRightarrow%20y%3D40)
So,three ordered pairs(x,y) that exist on the line : (0,200), (300,0) and (240,40)
Plot these point on graph and join them.
Answer:
22.90 is the answer i can't write somet
use my computer has problems
I = P*r*t = 800*0.06*2 =
Answer:
1/18
Step-by-step explanation:
We are considering that we have 2 dices with 6 faces each (so, the probability to getting any face in any dish is 1/6). To get an 11, we only have two ways to obtain it:
Dice 1= 6 and Dice 2 =5 or Dice 1= 5 and Dice 2 =6
So, the probability of the event is given as:
P(Dice1=5 ∧ Dice2=6) ∪ P(Dice1=6 ∧ Dice2=5) = P(Dice1=5) x P(Dice2=6) + P(Dice1=6) x P(Dice2=5) = 1/6 x 1/6 + 1/6 x 1/6 = 1/36 + 1/36 = 2/36 = 1/18.
As 1/18 = 0,055, and 0,055 > 0,05, we consider the event as not significative (according to the definition of significance in the sentence).
Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or
ft
=
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
=
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k(
)
k = 18
Work done (W) to stretch the spring by
ft will be
W = ![\int\limits^\frac{11}{12} _0 {kx} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B11%7D%7B12%7D%20_0%20%7Bkx%7D%20%5C%2C%20dx)
= ![\int\limits^\frac{11}{12} _0 {(18x)} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B11%7D%7B12%7D%20_0%20%7B%2818x%29%7D%20%5C%2C%20dx)
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9(
)²
= 7.56 lb-ft