Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
A fraction is just the easier, cleaner way of writing a division problem
the numerator is the number you are dividing
the denominator is the number you are dividing with
EX- 2 divided by 3 as a fraction is
2/3
<h2>Domain: {0, 2}</h2><h2>Range: {0, 1, 1}</h2><h2 /><h3>When dealing with the domain, remember that no numbers can repeat in the domain so if there is more than one of the same number, we only list it one.</h3><h3 /><h3>When dealing with the range, it's ok if numbers repeat because it's the y-value not the x-value.</h3><h3 /><h3 />
You would do 157.5/35 to find how much gas she needs
157/35=4.5
She'll need 4.5gallons of gas