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Tanzania [10]
3 years ago
10

A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

t from its natural length to 11 in. beyond its natural length?
Mathematics
1 answer:
sattari [20]3 years ago
6 0

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or \frac{8}{12} ft

= \frac{2}{3} ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= \frac{11}{12} ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k(\frac{2}{3})

k = 18

Work done (W) to stretch the spring by \frac{11}{12} ft will be

W = \int\limits^\frac{11}{12} _0 {kx} \, dx

    = \int\limits^\frac{11}{12} _0 {(18x)} \, dx

    = 18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0

    = 9(\frac{11}{12})²

    = 7.56 lb-ft

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Novosadov [1.4K]

Answer:

XY = 8 and YZ = 20

Step-by-step explanation:

If XY and YZ are on the one line, we can write

XY + YZ = 28

(2x+2) + (9x - 7) = 28

2x+2 + 9x - 7 = 28

11x - 5 = 28

11x = 33

x = 3

XY = 2x+2 = 2*3 + 2 = 8

YZ = 9x - 7 = 9*3 - 7 = 27 - 7 = 20

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12345 [234]

Answer:

y = 3x-16

Step-by-step explanation:

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3 years ago
Can someone help me with this question please.
Daniel [21]
For part A. 0.85

For part b. 11.9


Explain


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The problem give us a has 11 trackers and the total cost of download is 9.35 pounds


9.35/11

= 0.85


Now we are given each track cost in album b cost the same as track on A

Cost of each track in album B is 0.85

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Strike441 [17]
3/10 that's equivalent
8 0
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Read 2 more answers
Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).
Airida [17]

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

z1=\frac{2}{5} (cos63  + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles  as

A+B = 63+117 =180

z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)

=\frac{-10}{3}

Since sin180=0 and cos 180=-1

7 0
4 years ago
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