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Lisa [10]
3 years ago
15

What is 134,500 rounded to the nearest ten thousand

Mathematics
1 answer:
Marina CMI [18]3 years ago
7 0
134,500 rounded is 13,000
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A physical trainer decides to collect data to see if people are actually weight changing weight during the shelter in place. He
telo118 [61]

Answer:

H0: µd = 0 (claim)

H1: µd ≠ 0

This is a two-tail t-test for µd

Step-by-step explanation:

This is a paired (dependent) sample test, with its hypothesis is written as :

H0: µd = 0

H1: µd ≠ 0

From the equality sign used in the hypothesis declaration, a not equal to ≠ sign in the alternative hypothesis is used for a two tailed t test

The data isn't attached, however bce the test statistic cannot be obtained. However, the test statistic formular for a paired sample is given as :

T = dbar / (Sd/√n)

dbar = mean of the difference ; Sd = standard deviation of the difference.

3 0
2 years ago
#10
amm1812

Answer:

There are 3 green marbles in the box.

Step-by-step explanation:

15% = 0.15

To figure out how much 15% of 21 is, you must multipl the decimal form of the percentage by the whole number. This will give you how much of that number that percentage is.

0.15 * 21 = 3.15  

But you can't have 0.15 of a marble, so you must round as well.

3 green marbles in the box.

3 0
3 years ago
a school had 690 students sign up for the trivia teams if they wanted to have nine teams with the same number of students on eac
Anna11 [10]

Answer:

30 more students

Step-by-step explanation:

690 + 30 = 720

720 / 9 = 80


8 0
3 years ago
Help me pls only 10points
NeX [460]

y=-7x+8

y=-7x-8

-7x+8=-7x-8

8=-8

x∈∅

B. No solutions

3 0
3 years ago
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

4 0
3 years ago
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