All categories

3 years ago

To the nearest tenth the value of x that satisfies 2x = −2x + 11 is

1 answer:

4 0

To solve for variable equations or inequalities, we want to do two things:
1. Reduce one side to variables only
2. Reduce that side to the variable without coefficients.

The given equation is $2x=-2x+11$ .

Let's perform step 1: reducing one side to variables only. By adding $2x$ to both sides of the equation, we get $4x=11$ .

Now let's perform step 2: reducing that side to the variable without coefficients. Since the coefficient of $4x$ is $4$ , we need to divide both sides of the equation by 4: $x=\frac{11}{4}=2.75$ . Rounded to the nearest tenth, $x=2.8$ .

So the value of $x$ that satisfies $2x=-2x+11$ is $x=2.8$ .

You might be interested in

A rectangular prism has a volume of 1376 cubic inches. The prism is 10 inches wide and 18 inches long. What is the height of the

Vladimir79 [104]

$\huge\boxed{ \mathcal{\longmapsto Answer࿐}}$

we know,

$\boxed{volume = l \times w \times h}$

$\longmapsto1376 = 18 \times 10 \times h$

$\longmapsto h = \dfrac{1376}{180}$

$\longmapsto h = 7.64 \: \: inches$

3 0

2 years ago

Help plzzzzzzzzzzzzzzzzzzzzz

andreyandreev [35.5K]

Answer:

20??? wow I feel stupid I forgot how to do everything

4 0

2 years ago

HELPPP PLEASE DUE IN 20 minutes

kupik [55]

Answer:

i think its a trick question

Step-by-step explanation:

theres no way theres a righr answer the 20$ on is always ahead

6 0

3 years ago

Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

3 years ago

The sum of three consecutive even numbers is 114 what's the smallest of these numbers

laila [671]

Answer:

Step-by-step explanation:

consecutive even numbers are 2,4, 6...

Let the smallest of the 3 numbers be x.

2nd number= x+2

3rd number

=x+2+2

= x+4

sum of the 3 numbers= x +x+2 +x+4

114= 3x+6

3x= 114 -6 (-3 on both sides)

3x= 108 (simplify)

x= 108 ÷3

x= 36

Thus, the smallest number is 36.

Let's check!

36+38+40= 114 ✓

8 0

3 years ago