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3 years ago

Can you plz help me with this problem I’ve been stuck on it for a long time

Mathematics

2 answers:

lukranit [14]3 years ago

8 0

Answer:

B 1 inch = 16 ft

Step-by-step explanation:

We can use proportions to solve. Put the drawing over the real life

3.5 inches 1 inch

----------------- = ------------

56 ft x ft

Using cross products

3.5 x = 56

Divide each side by 3.5

3.5x/3.5 = 56/3.5

x =16

So 1 inch = 16 ft

Tpy6a [65]3 years ago

6 0

I think the answer is B

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Find the perimeter of ABHG. Round your answer to the nearest tenth of an inch.

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Answer:

141.5

Step-by-step explanation:

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3 years ago

Factor 3y3 – 9y2<br> The factored polynomial is

allochka39001 [22]

Answer:

Factor 3y23y2 out of 3y33y3.

3y2(y)−9y23y2(y)-9y2

Factor 3y23y2 out of −9y2-9y2.

3y2(y)+3y2(−3)3y2(y)+3y2(-3)

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Step-by-step explanation:

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3 years ago

A bird flies 2/3 of a mile per a minute. How many miles per an hour is it flying?

Archy [21]

Answer: 40

Step-by-step explanation:

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3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago

e Carlos rented a truck for one day. There was a base fee of $ 20.99 , and there was an additional charge of 88 cents for each m

Sonja [21]

Let Base fee be X and No. of Miles be Y.

According to the question
Total Charge= (X+ 88Y)
251.55=20.99+ 0.88Y
Y= 251.55-20.99/0.88
Y= 262 miles

7 0

3 years ago

Read 2 more answers