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NeX [460]
3 years ago
10

One number is 2 less than a second number. Twice the second number is 17 less than 5 times the first

Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0
X=y-2
2y=5x-17
Substituting for x into the second equation, we find
2y=5(y-2)-17
2y=5y-10-17
-3y=-27
y=9
So x=7
Thus, the two numbers are 7 and 9.
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What is the constant of variation k of the line y=kx through (5,8)
mina [271]

Answer:

k= 8/5

Step-by-step explanation:

here x= 5 and y= 8

we have y=kx

k= y/x

k= 8/5 this is constant of variation

8 0
3 years ago
Read 2 more answers
he Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers tak
WINSTONCH [101]

Answer:

30.5 ; 49 ; 27 ; 50 ; 45

Step-by-step explanation:

Determine the first and third quartiles. Determine the second decile and the eighth decile. Determine the 67th percentile

Given the ordered data :

13 13 13 20 26 27 29 32 34 34 35 35 36 37 38 41 41 41 42 44 46 47 48 50 53 55 56 62 67 82

Sample size, n = 30

The first quartile ;Q1

Q1 = 1/4(n+1)th term

Q1 = 31/4 = 7.75th term

Q1 = (29+32)/2

Q1 = 30.5

Q3 ;

Q3 = 3/4(n+1)th term

Q3 = 3(31)/4 = 23.25 th term

Q3 = (48 + 50) /2 = 49

2nd decile :

0.2 * (nth term

0.2 * 30 = 6th term = 27

8th decile :

0.8 * 30 = 24 th term

= 50

67th percentile :

0.67 * (n+1)th term

0.67 * 31 = 20.77

= (44 + 46) / 2

= 45

3 0
3 years ago
Allie wants to arrange her flower garden in eight equal rows.
Shalnov [3]
So depending on the amount of Flowers in a row or feet in a row you would divide the total by eight.
7 0
3 years ago
Write a quadratic equation given the roots -1/3 and 5, show your work
Travka [436]

\boxed{(x - a)(x - b) = 0}

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

x =  -  \frac{1}{3}  \\ x = 5

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

(x +  \frac{1}{3} )(x -  5) = 0

Here we can convert the expression x+1/3 to this.

x +  \frac{1}{3}  = 0 \\  3x + 1 = 0

Rewrite the equation.

(3x + 1)(x - 5) = 0

Simplify by multiplying both expressions.

3 {x}^{2}  - 15x + x - 5 = 0 \\ 3 {x}^{2}  - 14x  - 5 = 0

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

3 {(5)}^{2}  - 14(5)  - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0

3( -  \frac{1}{3} )^{2}  - 14( -  \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) +  \frac{14}{3}  - 5 = 0 \\  \frac{1}{3}  +  \frac{14}{3}  -  \frac{15}{3}  = 0 \\  \frac{15}{3}  -  \frac{15}{3}  = 0 \\ 0 = 0

The equation is true for both roots.

<u>Answer</u>

\large \boxed {3 {x}^{2}  - 14x - 5 = 0}

8 0
2 years ago
How do u solve 4(3x-1)=9-x
Nastasia [14]

Answer:

x = 1

Step-by-step explanation:

Well the first step is to apply the distributive property:

4(3x - 1) is equal to (12x - 4). You DISTRIBUTE a '4' to what is inside the parentheses.

And btw, to make it easier, you can make 9 - x so that x is first. For example, (-x + 9). They're both the same thing, just written differently.

Your new equation is 12x - 4 = -x + 9. You want to now solve the equation.

Add the (-x) to both sides. It cancels out on the right side and you add it to 12x on the left side.

[If there's no number in front of a variable, you can always just put 1 in order to make it easier]

12x + 1x = 13x. Your new equation is 13x - 4 = 9. This should look very familiar. You simply add 4 to both sides. 9 + 4 = 13

Finally, 13x = 13. Divide 13 ÷ 13 to get 1.

x = 1

5 0
3 years ago
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