The square of the sum of x and -3 is equal to y how can turn this problem into a numbers

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

Graph y = x2 + 10x + 25.<br> Determine the number of solutions.

vesna_86 [32]

Answer:

1 solution

Step-by-step explanation:

The equation will be a horizontal parabola that has an x-intercept of (-5,0) therefore 1 solution

7 0

3 years ago

Read 2 more answers

If two angles are supplement of each other, then one of the angles must be acute

oksian1 [2.3K]

Answer:

this is true

Step-by-step explanation:

a supplementary angle adds up to 180 degrees. two accute angles would equal to around 90 and two obtuse angles would add up to more than 180. two right angles are perpendicular and they could work but since the question asks about acute and obtuse, its true that one angle must be acute and the other must be obtuse for it to add up to 180.

7 0

3 years ago

Please show work it’s due tommorow I will give 35 Brainly

SCORPION-xisa [38]

Answer:

Step-by-step explanation:Worked out on paper shown below

Also I recommended a online app called (it has wierd name but it’s helpful for algebra) mathpapa

Also I do math in pen so the last answer is messed up it’s 4c^2d and then the rest of the parentheses.Sorry for that.