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NNADVOKAT [17]
3 years ago
12

*Please help, I will mark brainliest!*

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

If we are to treat these as two ordered pairs, then the rate of change is 1.25.

Step-by-step explanation:

To find this, use the slope equation with the ordered pairs.

m(slope) = (y2 - y1)/(x2 - x1)

m = (11 9/16 - 9 1/16)/(12 - 10)

m = (2 8/16)/2

m = 2.5/2

m = 1.25

Now we know that this could be a function since we have a constant slope.

You might be interested in
Simplify each expression using the distributive property <br><br>9(-7q-6)​
hammer [34]

Answer:

-63q-54

Step-by-step explanation:

When using the distributive property, you multiply everything inside of the parentheses by the number outside of the parentheses.

9(-7q-6)

-63q-54

Hope this helps, and have a great day o(* ̄▽ ̄*)ブ

5 0
3 years ago
ANSWER PLZ QUICK AND FAST
kotykmax [81]

Hi!

The answer is C. It is a numerical expression because it contains only numbers and operation symbols.

4 0
3 years ago
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.
Naya [18.7K]
It's a geometric sequence.

4,-12,36,... \\ \\&#10;a_1=4 \\&#10;r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\&#10;a_n=a_1 \times r^{n-1} \\&#10;a_n=4 \times (-3)^{n-1} \\&#10;a_n=4 \times (-3)^{-1} \times (-3)^n \\&#10;a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\&#10;a_n=-\frac{4}{3}(-3)^n

It's the sum for term 4 through term 15.

 \boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}
8 0
3 years ago
Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


5 0
2 years ago
Read 2 more answers
Harriet thinks of a number.
umka2103 [35]
Let the original number be x
X^2 + 11 = 36
Subtract 11
X^2 = 25
Square root both
X = 5
Solution: her original number is 5
6 0
2 years ago
Read 2 more answers
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