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IceJOKER [234]
3 years ago
13

(05.05 HC)The four points (−2, 5), (−2, −1), (5, −1), and (3, 5) are the vertices of a polygon. What is the area, in square unit

s, of this polygon?
27 units^2
33 units^2
36 units^2
51 units^2

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0
The points define a trapezoid of height 6 and midsegment length 6. The area is
  6×6 = 36 units²

JulsSmile [24]3 years ago
5 0

Hello,

The correct answer is C) 36 units^2

Hope this helps!!!! (:

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A=2(wl+hl+hw)

Step-by-step explanation:

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2 years ago
Mindy conducts an experiment with three quarters. She counts the number of heads and tails for each flip of the three quarters.
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i don't have the table so no one can answer

Step-by-step explanation:

4 0
2 years ago
A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the
zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power =  1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

d = \frac{1}{2} ({v-0})t

5.5= \frac{1}{2} (1.6v)

The speed of the sprinter then become:

v = 6.875 m/s

Part (b)

Convert the weight of the sprinter to mass:

m = \frac{w}{g}

m = \frac{706}{9.8}

m = 72 kg

KE (Kinetic Energy) can then be calculated as:

KE = \frac{1}{2} mv^{2}

KE = \frac{1}{2} (72)(6.875)^{2}

KE = 1701.56 J = 1.70 kJ

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

P = \frac{KE}{t} \\\

P = \frac{1701.56}{1.6}

P = 1063.48 W = 1.06 kW

5 0
3 years ago
If Frank can produce either 20 pizzas or 40 cheesecakes per day, the opportunity cost per
navik [9.2K]
20p = 40ck
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4 0
2 years ago
Find the missing side lengths leave your answer as a racials simplest form
Aleksandr-060686 [28]

Answer:

m=7\sqrt3

n=7

Step-by-step explanation:

Hi there!

We are given a right triangle (notice the 90°) angle, the measure of one of the acute angles as 60°, and the measure of the hypotenuse (the side OPPOSITE from the 90 degree angle) as 14

We need to find the lengths of m and n

Firstly, let's find the measure of the other acute angle

The acute angles in a right triangle are complementary, meaning they add up to 90 degrees

Let's make the measure of the unknown acute angle x

So x+60°=90°

Subtract 60 from both sides

x=30°

So the measure of the other acute angle is 30 degrees

This makes the right triangle a special kind of right triangle, a 30°-60°-90°  triangle

In a 30°-60°-90° triangle, if the length of the hypotenuse is a, then the length of the leg (the side that makes up the right angle) opposite from the 30 degree angle is \frac{a}{2}, and the leg opposite from the 60 degree angle is \frac{a\sqrt3}{2}

In this case, a=14, n=\frac{a}{2}, and m=\frac{a\sqrt3}{2}

Now substitute the value of a into the formulas to find n and m to find the lengths of those sides

So that means that n=\frac{14}{2}, which is equal to 7

And m=\frac{14\sqrt3}{2}, which simplified, is equal to 7\sqrt3

Hope this helps!

7 0
3 years ago
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