I honestly think it is B, i really really hoped this helped you
There are 4 Queens, 4 Kings, and 4 Aces in a standard deck of cards.
Add these together, and there are 12 cards that you have a chance of choosing from.
The ratio of cards we want to get (queen, king ace) to number of cards is 12/52. This is the probability. We can simplify it further by dividing both sides by 4. We now have the fraction 3/13.
Therefore, the probability of drawing a queen, king, or ace is 3 in 13, or 23%.
hope this helped!
You can use the Law of Sines for this problem, but what makes it tough at first glance is that they put a step in before you can use it directly. That first step is to get m∠C. When solving a triangle, always get the third angle if you know the other two so that you can use the Law of Sines (or Law of Cosines) more directly.
The sum of the angles of any triangles is 180°. We know the measures of the two other angles. So we subtract them from 180° to find that third angle.
180° - 76° - 66° = 38°
Now we can use the proportion from the picture. Angle B measures 76°, side b is our unknown, Angle C measures 38°, and side c measures 3 units.
sin 76° sin 38°
----------- = -----------
b 3
Cross multiply to find b (the side). We carry out five places in these calculations to get more accuracy.
3 * sin 76° = b * sin 38°
b = 3 * sin 76° 3 * 0.56611 1.69832
--------------- = --------------- = ---------------- = 5.73044
sin 38° 0.29636 0.29636
To the nearest tenth, b - 5.7 units.
Their sum would be of odd number....
-1/2 I think...I hope I helped
