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Tomtit [17]
3 years ago
9

Did I do this right? If not, how should I do it?

Mathematics
1 answer:
kkurt [141]3 years ago
3 0
Unfortunately, your answer is incorrect, but I totally understand your thinking. However, 1/4 is the probability for each individual that they'll be placed in a general civil case. Since there are two of them, and the question is asking the probability that only one will be in a general civil case, you have to approach the problem slightly differently.

There is a 1/16 chance that both will be put in the case (1/4 * 1/4), a 9/16 chance that neither will be put in the case (3/4 * 3/4), and therefore leaving a 6/16 chance that only one of them will be placed in the civil case. (1 - (1/16 + 9/16). This is equivalent to the decimal 0.375.

Draw out a chart of all the 16 possibilities, and circle the ones where the criteria meet. You'll find that there are 6 instances where one of them is put in a general civil case alone.
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Phoenix [80]

Answer:

\frac{3a}{a-2}

Step-by-step explanation:

\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}

Factorise 2a^2 - 11a + 14}

\frac{2a - 7}{a}*\frac{3a^2}{(2a - 7)(a - 2)}

2a - 7 cancels  2a - 7

\frac{1}{a}*\frac{3a^2}{(1))(a - 2)}

\frac{1(3a^2)}{a(a-2)}

\frac{a(3a)}{a(a-2)}

"a" cancels "a"

\frac{3a}{a-2}

Thus,

\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14} = \frac{3a}{a-2}

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weqwewe [10]

Answer:

\dfrac{2^3•5^2}{2^5•3•5^4}

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Fourth option is the right answer.

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Answer:

C)\:\:\frac{\sqrt 2}{ 2 }

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