Answer: 5225472000
Step-by-step explanation:
Given : The number of bulls = 6
The number of horses = 10
Since Aidan needs to place them in a line of 16 paddocks, and the bulls cannot be placed in adjacent paddocks .
Also there are two ways to arrange the group pf bulls and horses.
Then , the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks will be :_
![2\times6!\times10!=5225472000](https://tex.z-dn.net/?f=2%5Ctimes6%21%5Ctimes10%21%3D5225472000)
Hence, the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks =5225472000
Answer:
6; 54 is 6 times 9
Step-by-step explanation:
9x = 54
x = 54/9
x = 6
Answer:
62
Step-by-step explanation:
The answer is 17! Hope it helps :)
Answer:
![\huge\boxed{d=\sqrt{17}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7Bd%3D%5Csqrt%7B17%7D%7D)
Step-by-step explanation:
Simply use the fact that the change in x squared + the change in y squared = the distance squared. (The Pythagorean Theorem)
1^2 + 4^2 = d^2
1 + 16 = d^2
17 = d^2
d = √17
Hope it helps :)