Answer: y=4
Step-by-step explanation:
We have a khown angle wich is 30 degree .
Cos 30 = root square of 3 /2
So root sqaure of 3/2 = 4 root square 3 / x
X= 4 r.sq 3 / r.sq 3/2 = 8
So we just need to apply the pythagorian theorem
X^2= y^2+ 48
64 = y^2 +48
Y^2 = 16
Y=4
Log base 4 of 32 is equal to 5/2.
What a log is looking for is what number do we have to raise 4 to in order to get 32. Since it is not an exact multiply of 4, we have to look for fractions. Since we know that 2 can multiply directly to 32, we would simply take the square root of 4. This can be done by raising 4 to the 1/2.
Now that we have 2, we know that raising that to the 5th power would give us 32. So we'll take that answer and the 1/2 from before and multiply them together to get the final answer.
5*1/2 = 5/2.
Answer:
B if you mean log_7 (1)*log_ 5 (25)
Step-by-step explanation:
I think you mean 7 and 5 as bases... like
log_7(1)*log_5(25)
log_7(1)=0 because 7^0=1
log_5(25)=2 because 5^2=25
So you have to perform the following operation 0*2=0
so 0 is definitely one answer
1 and 5*7 are definitely not equal to 0
let's look at last choice now
log_7(7)=1 because 7^1=7
so D is equivalent to saying 2*1 which is 2 not 0
so only one choice works and it is B
Answer:
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Class 11
>>Physics
>>Units and Measurement
>>Errors in Measurement
>>You measure two quantities ...
Question
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You measure two quantities as A=1.0m±0.2m, B=2.0m±0.2m. We should report correct value for
AB
as
Medium
Solution
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Correct option is
D
1.4m±0.2m
Here, A=1.0m±0.2m, B=2.0m±0.2m
AB=(1.0m)(2.0m)=2.0m
2
AB
=
2.0m
=1.414m
Rounding off to two significant figures, we get
AB
=1.4m
AB
ΔAB
=
2
1
(
A
ΔA
+
B
ΔB
)=
2
1
(
1.0
0.2
+
2.0
0.2
)=
2
0.3
Δ
AB
=
2
0.3
×
AB
=
2
0.3
×1.414=0.212m
Rounding off to one significant figure, we get
Δ
AB
=0.2m
The correct value for
AB
is 1.4m±0.2m
Answer:
k = ½
Equation => 
Step-by-step explanation:
Constant of proportionality (k) = y/x
Using a point on the graph, (6, 3),
k = y/x = 3/6 = ½
k = ½
Equation of the line:
Plug in the value of k into
(slope-intercept form of equation for proportional relationship)
Thus:
