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lord [1]
3 years ago
8

He nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports t

hat the wind is coming from the west at 68 miles per hour. in order to travel in a straight line, the ring wraiths decide to head northwest. at what speed should they fly (omit units)?

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

This problem is better understood with a given figure. Assuming that the flight is in a perfect northwest direction such that the angle is 45°, therefore I believe I have the correct figure to simulate the situation (see attached).

 

Now we are asked to find for the value of the hypotenuse (flight speed) given the angle and the side opposite to the angle. In this case, we use the sin function:

sin θ = opposite side / hypotenuse

sin 45 = 68 miles per hr / flight

flight = 68 miles per hr / sin 45

<span>flight = 96.17 miles per hr</span>

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steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

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3 years ago
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Studentka2010 [4]

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64 * b * b * b * b * b * b

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4 0
3 years ago
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antiseptic1488 [7]

Answer:

Step-by-step explanation:

Big circle:

R = radius = diameter ÷2 = 42 ÷ 2 = 21 cm

Area of big circle= πR²

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Diameter of small circle  = radius of big circle = 21 cm

r = 21/2 = 10.5 cm

Area of small circle = πr²

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Area of shaded region = area of big circle - area of small circle

= 1386 - 346.5

= 1039.5 cm²

                                 

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