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3 years ago

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Jean transformed a point by using the rule (x,y)(x-6,y+8) the image point is (-4,1) which point is the pre image

2 answers:

Xelga [282]3 years ago

8 0

To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).

(-4+6,1-8)

(2,-7) should be the pre image point.

Alla [95]3 years ago

3 0

rule (x,y)(x-6,y+8)

(-4,1):

Preimage: x = -4 + 6 = 2 and y = 1 - 8 = -7

Answer

Pre image (2 , -7)

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2 years ago

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Ilia_Sergeevich [38]

Answer:

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2 years ago

Please help me with this question!!!

scoundrel [369]

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2 years ago

The coordinates of the vertices of AJKL are J(-5, -1), K(0, 1), and L(2, -5).

dalvyx [7]

We need slope of all lines ?

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$\\ \sf\longmapsto m=\dfrac{1+1}{0+5}=\dfrac{2}{5}$

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$\\ \sf\longmapsto m=\dfrac{-5-1}{2-0}=\dfrac{-6}{0}=-3$

Slope of JL

$\\ \sf\longmapsto m=\dfrac{-5-1}{2+5}=\dfrac{-6}{7}$

7 0

1 year ago