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3 years ago

I need help on this question plz

Mathematics

2 answers:

dmitriy555 [2]3 years ago

8 0

Mode are repeating numbers in a sequence therefore 23 is your mode

Alex3 years ago

3 0

The mode refers to the numbers or values that appears the most often in your set of data (which one shows up the most). So in this case it would be 23, as it shows up twice, whereas every other number only shows up once.

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How much is 1.4 kg minus 650 grams

faltersainse [42]

First of all you have to convert kg to grams

so there is 1 kg in 1000g
.4 kg is 400g
1000+400= 1400g

1400-650 = 750 kg

that's your final answer

8 0

3 years ago

A bowling alley charges $15 per game. Customers are not charged to rent bowling shoes.

Dimas [21]

The description shows a linear relationship and a proportional relationship.

<h3>How to describe the given relationship?</h3>

The given parameters are:

Charger = $15 per game

Customers are not charged to rent bowling shoes.

The statement "Customers are not charged to rent bowling shoes" means that the linear function has no y-intercept

So, the linear function can be represented as

y = Charges * x

This gives

y = 15x

Linear functions that are proportional functions are represented as y = mx

In this case, y = mx represents y = 15x

Hence, the description shows a linear relationship and a proportional relationship.

Read more about proportional relationship at

brainly.com/question/12242745

#SPJ1

8 0

1 year ago

The given line passes through the points and (-4, -3) and (4, 1).

Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

(x2 , y2) is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

perpendicular line to this line is -1/m

- The point-slope of the equation is $y - y_{1}=m(x - x_{1})$

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line $m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}$

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0

3 years ago

What is the area of the given figure?

Scilla [17]

Answer:

Option A

Step-by-step explanation:

Area of the given figure = area of triangle + area of rectangle

A = side x height/2 + width x length

= 5 x (8-1-2)/2 + 5 x 8

= 52.5 in2

6 0

3 years ago

Find the values of m for which the lines y=mx-2 are tangents to the curve with equation y=x^2-4x+2

deff fn [24]

Let y= mx-2 be the tangent line to y=x^2-4x+2 at x=a.

Then slope, $m=\frac{dy}{dx} at x=a = 2a-4.$

Hence the equation is y=(2a-4)x-2

Let's find y-coordinate at x=a using tangent line and curve.

Using tangent line y at x=a is (2a-4) a -2 $=2a^{2}-4a-2$

Using given curve y-coordinate at x=a is $a^{2}-4a+2$

Let's equate these 2 y-coordinates,

$2a^{2} -4a-2 = a^{2} -4a+2$

$2a^{2}-a^{2} = 2+2$

$a^{2}=4$

a=2 or -2.

If a=2, $m=2a-4 = 2*2-4=0$

If a=-2, $m= 2(-2)-4 = -8$

Hence m values are 0 and -8.

8 0

3 years ago