Solve 2 cos theta + 2 = 3 in the interval from 0 to 2pi. Round to the nearest hundredth.

1 answer:

4 0

2cos theta = 1 -> cos theta = 1/2

Then theta = pi/3 + 2npi or -pi/3 + 2npi, where n is random interger

And the domain is restricted in [0,2pi]

So answer will be pi/3 or 5pi/3

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cupoosta [38]

Answer:

Step-by-step explanation:

Substitute the coordinates of the point into the left side of the inequality, evaluate and compare.

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3 years ago

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Rudik [331]

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3 years ago

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Can you help me with this question?

Rufina [12.5K]

Answer:

16.2

Step-by-step explanation:

The angle internal to the triangle at B is the supplement of the one shown, so is 65°. That is equal to the angle internal to the triangle at D. Since the vertical angles at C are congruent, the two triangles are similar by the AA theorem.

Corresponding sides of similar triangles are proportional, so we can write the proportion shown in the attachment:

BC/FC = DC/AC

BC = FC(DC/AC) = 21.6(7.2/9.6)

BC = 16.2 . . . . matches the first choice