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4 years ago

7(n – 1) = -2(3 + n) solve for n

Mathematics

2 answers:

weqwewe [10]4 years ago

8 0

N=1/9 hope this helps

KengaRu [80]4 years ago

8 0

PEMDAS: Parentheses, Exponents, Multiply, Divide, Add, Subtract.
By using PEMDAS, we can already make the equation easier by Multiplying the variables INSIDE the parentheses by whats OUTSIDE of them.
7n-7=-6-2n
Now we combine like terms.
-2n+2n=0 and 7n+2n=9n; 9n-7=-6
-7+7=0 and -6+7=-1; 9n=-1
Now we divide both sides by the coefficient, which is the number in front of the variable.
9n/9=n and -1/9=-0.1111111 repeating.
And now you know the value of n: n=0.1111 repeating (TIP: draw a line OVER the number behind the decimal thats repeating)

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The conditional probability of an event, say A, given that another event, say B, has already occurred is,

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

$P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30$

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. $P (M^{c} | V)$ as follows:

$P (M^{c} | V)=1-P(M|V)=1-0.30=0.70$

Thus, the value of $P (M^{c} | V)$ is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

$P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375$

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. $P(V^{c}|M)$ as follows:

$P(V^{c}|M)=1-P(V|M)=1-0.375=0.625$

Thus, the value of $P(V^{c}|M)$ is 0.625.

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3 years ago